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First, we briefly review a 5-dimensional EMD model with two Maxwell fields [87]. The action of this model is
$ \begin{aligned}[b] S=& \int -\frac{1}{16\pi G_{5}}\sqrt{-g}(R-\frac{f_{1}(\phi)}{4}F_{(1)MN}F^{MN}\\&- \frac{f_{2}(\phi)}{4}F_{(2)MN}F^{MN}-\frac{1}{2}\partial_{M}\phi\partial^{M}\phi-V(\phi) ){\rm d}^{5}x, \end{aligned} $
(1) where
$ F_{(1)MN} $ and$ F_{(2)MN} $ are the field strength tensors, ϕ is the dilaton field, and R is Ricci scalar. We can consider$ A_1 $ as the dual of a (neutral) flavor current, capable of creating mesons, while$ A_2 $ is the dual of the electromagnetic current.$ f_{1}(\phi) $ and$ f_{2}(\phi) $ are the gauge kinetic functions representing the coupling with the two U(1) gauge fields respectively.$ V(\phi) $ is the potential of the dilaton field, whose explicit form will depend on the scale function$ A(z) $ , and$ G_5 $ is the Newton constant in five-dimensional spacetime. The presence of magnetic field is introduced by adding a U(1) gauge field which is dual of the electromagnetic current in the gravitational action. For our current purposes, we will just introduce a constant magnetic field B, that is, we have no interest in the fluctuations of the Abelian gauge field. We assume the form of metric is$ \begin{aligned}[b] {\rm d}s^{2}=&\frac{L^{2} S(z)}{z^{2}}\Bigg[(-g(z){\rm d}t^{2}+\frac{1}{g(z)}{\rm d}z^{2}+{\rm d}y^{2}_{1}\\&+{\rm e}^{B^{2}z^{2}}({\rm d}y^{2}_{2}+{\rm d}y^{2}_{3})\Bigg], \end{aligned} $
(2) where
$ S(z) $ is the scale factor and we set the AdS radius L to one in this paper. Note that B is the five-dimensional magnetic field which is related to four-dimensional magnetic field with a factor of$ {1}/{L} $ [94]. Thus, the unit of B is GeV. From the action, we can obtain below equations of motion (EoMs) [87]$ \begin{equation} g^{\prime \prime}(z)+g^{\prime}(z)\left(2 B^{2} z+\frac{3 S^{\prime}(z)}{2 S(z)}-\frac{3}{z}\right)-\frac{z^{2} f_{1}(z) A_{t}^{\prime}(z)^{2}}{L^{2} S(z)}=0, \end{equation} $
(3) $ \begin{aligned}[b] &\frac{B^{2} z {\rm e}^{-2 B^{2} z^{2}} f_{2}(z)}{L^{2} S(z)}+2 B^{2} g^{\prime}(z)\\ + & g(z)\left(4 B^{4} z+\frac{3 B^{2} S^{\prime}(z)}{S(z)}-\frac{4 B^{2}}{z}\right)=0, \end{aligned} $
(4) $ \begin{aligned}[b]& S^{\prime \prime}(z)-\frac{3 S^{\prime}(z)^{2}}{2 S(z)}+\frac{2 S^{\prime}(z)}{z}\\ + &S(z)\left(\frac{4 B^{4} z^{2}}{3}+\frac{4 B^{2}}{3}+\frac{1}{3} \phi^{\prime}(z)^{2}\right)=0, \\ \end{aligned} $
(5) $ \begin{aligned}[b] &\frac{g^{\prime \prime}(z)}{3 g(z)}+\frac{S^{\prime \prime}(z)}{S(z)}+S^{\prime}(z)\left(\frac{7 B^{2} z}{2 S(z)}+\frac{3 g^{\prime}(z)}{2 g(z) S(z)}-\frac{6}{z S(z)}\right)\\ + & g^{\prime}(z)\left(\frac{5 B^{2} z}{3 g(z)}-\frac{3}{z g(z)}\right)+2 B^{4} z^{2}+\frac{B^{2} z^{2} {\rm e}^{-2 B^{2} z^{2}} f_{2}(z)}{6 L^{2} g(z) S(z)}\\ - & 6 B^{2}+\frac{2 L^{2} S(z) V(z)}{3 z^{2} g(z)}+\frac{S^{\prime}(z)^{2}}{2 S(z)^{2}}+\frac{8}{z^{2}}=0, \end{aligned} $
(6) $ \begin{aligned}[b] &\phi^{\prime \prime}(z)+\phi^{\prime}(z)\left(2 B^{2} z+\frac{g^{\prime}(z)}{g(z)}+\frac{3 S^{\prime}(z)}{2 S(z)}-\frac{3}{z}\right)\\ +& \frac{z^{2} A_{t}^{\prime}(z)^{2}}{2 L^{2} g(z) S(z)} \frac{\partial f_{1}(\phi)}{\partial \phi} \\ -& \frac{B^{2} z^{2} {\rm e}^{-2 B^{2} z^{2}}}{2 L^{2} g(z) S(z)} \frac{\partial f_{2}(\phi)}{\partial \phi}-\frac{L^{2} S(z)}{z^{2} g(z)} \frac{\partial V(\phi)}{\partial \phi}=0, \end{aligned} $
(7) $ A_{t}^{\prime \prime}(z)+A_{t}^{\prime}(z)\left(2 B^{2} z+\frac{f_{1}^{\prime}(z)}{f_{1}(z)}+\frac{S^{\prime}(z)}{2 S(z)}-\frac{1}{z}\right)=0. $
(8) We impose the following boundary conditions,
$ \begin{aligned}[b] &g(0)=1\quad \rm { and } \quad g\left(z_{h}\right)=0, \\ &A_{t}(0)=\mu \quad\rm { and }\quad A_{t}\left(z_{h}\right)=0, \\ &S(0)=1, \\ &\phi(0)=0. \end{aligned} $
(9) Magnetic field is along the
$ y_1 $ direction and we set$ S(z) = {\rm e}^{2 A(z)} $ . In this model,$ A(e) $ and$ f_1(\phi) $ are fixed from QCD phenomena and$ V(\phi) $ is solved from the equation of motions. This scenario is named as the potential reconstruction approach, introduced in some early literature [58, 95, 96]. After those, there were many other works exploring this approach in holography. The form of the gauge coupling function$ f_1(\phi) $ can be constrained by studying the vector meson mass spectrum. We take the following simple form of$ f_{1}(z)={{\rm e}^{-c z^{2}-B^{2} z^{2}}}/{\sqrt{S(z)}} $ for the reason that the vector meson spectra can be shown to lie on linear Regge trajectories for$ B = 0 $ and the mass squared of the vector mesons satisfies$ m_{n}^{2}=4 c n $ . Moreover, the parameter c can also be fixed by matching with the lowest lying heavy meson states$ J / \Psi $ and$ \Psi' $ , and by doing this we get c = 1.16$ \rm GeV^2 $ [37, 87, 97]. The EoMs can be solved as$ \begin{aligned}[b] f_{2}(z)=&-\frac{L^{2} {\rm e}^{2 B^{2} z^{2}+2 A(z)}}{z} \\ &\times \left[g(z)\left(4 B^{2} z+6 A^{\prime}(z)-\frac{4}{z}\right)\right.+2 g^{\prime}(z)\Bigg], \end{aligned}$
(10) $ g(z)=1+ \int_0^{z} {\rm d}\xi \xi^{3} {\rm e}^{-B^{2}\xi^{2}-3A(\xi)}(K_{3}+\frac{\widetilde{\mu}^{2}}{2cL^{2}{\rm e}^{c\xi^{2}}}), $
(11) $ K_{3}=-\frac{1+\dfrac{\widetilde\mu^{2}}{2cL^{2}}\int_0^{z_{h}} {\rm d}\xi \xi^{3} {\rm e}^{-B^{2}\xi^{2}-3A(\xi)+c\xi^{2}}}{\int_0^{z_{h}} {\rm d}\xi \xi^{3} {\rm e}^{-B^{2}\xi^{2}-3A(\xi)}}, $
(12) $ \begin{aligned}[b] \phi(z)=& \frac{(9a-B^{2})\ln(\sqrt{6a^{2}-B^{4}}\sqrt{6a^{2}z^{2}+9a^{2}-B^{4}z^{2}-B^{2}}+6a^{2}z-B^{4}z)}{\sqrt{6a^{2}-B^{4}}} \\&+z\sqrt{6a^{2}z^{2}+9a-B^{2}(B^{2}z^{2}+1)}-\frac{(9a-B^{2})\log(\sqrt{9a-B^{2}}\sqrt{6a^{2}-B^{4}})}{\sqrt{6a^{2}-B^{4}}}, \end{aligned} $ (13) $ \begin{aligned}[b] A_{t}(z)=&\mu\left[1-\frac{\int_{0}^{z} {\rm d} \xi \dfrac{\xi {\rm e}^{-B^{2} \xi^{2}}}{f_{1}(\xi) \sqrt{S(\xi)}}}{\int_{0}^{z_{h}} {\rm d} \xi \dfrac{\xi {\rm e}^{-B^{2} \xi^{2}}}{f_{1}(\xi) \sqrt{S(\xi)}}}\right]\\=&\tilde{\mu} \int_{z}^{z_{h}} {\rm d} \xi \dfrac{\xi {\rm e}^{-B^{2} \xi^{2}}}{f_{1}(\xi) \sqrt{S(\xi)}}. \end{aligned} $
(14) The metric in the string frame is
$ \begin{equation} {\rm d} s_{s}^{2}=\frac{L^{2} {\rm e}^{2 A_{s}(z)}}{z^{2}}\left[-g(z) {\rm d} {t}^{2}+\frac{{\rm d} z^{2}}{g(z)}+{\rm d} y_{1}^{2}+{\rm e}^{B^{2} z^{2}}\left({\rm d} y_{2}^{2}+{\rm d} y_{3}^{2}\right)\right], \end{equation} $
(15) where
$ A_{s}=A(z)+\sqrt{{1}/{6}}\phi(z) $ . Following [37], we will assume$ A(z)=-a z^{2} $ and take$ a = 0.15\; \rm{GeV^2} $ for a decent match with the lattice QCD deconfinement temperature at B = 0. The Hawking temperature is given as$ \begin{equation} T=- \frac{z_{h}{\rm e}^{A(z_{h})-B^{2}z_{h}^{2}}}{4\pi}\left(K_{3}+\frac{\widetilde{\mu}^{2}}{2cL^{2}}{\rm e}^{c z_{h}^{2}}\right). \end{equation} $
(16) The Nambu–Goto action of a string in the worldsheet is given by
$ \begin{equation} S_{\rm NG} = - \frac{1}{2\pi\alpha'} \int {\rm d}^{2}\xi \sqrt{- \det g_{ab}}, \end{equation} $
(17) where
$ g_{ab} $ is the induced metric,$ \dfrac{1}{2\pi\alpha'} $ is the string tension and$ \begin{equation} g_{ab} = g_{MN} \partial_a X^M \partial_b X^N, \quad a,\,b=0,\,1. \end{equation} $
(18) Here,
$ X^M $ and$ g_{MN} $ are the coordinates and the metric of the AdS space.Then, the Nambu–Goto action of the string can be rewritten as
$ \begin{equation} S_{\rm NG} = - \frac{L^2}{2\pi\alpha'T}\int_{-L/2}^{L/2} {\rm d}{x}^{2} \sqrt{k_1(z) \frac{{\rm d}{z}^2}{{\rm d}{x}^2} + k_2(z)}. \end{equation} $
(19) In this case, we can parameterize in the parallel magnetic field direction.
$ k_1(z) $ and$ k_2(z) $ are$ k_1(z) =\frac{{\rm e}^{4A_{s}}}{z^{4}}, $
(20) $ k_2(z) =\frac{{\rm e}^{4A_{s}}g(z)}{z^{4}}. $
(21) Through the standard procedure, we can get the renormalized two-flavor free energy of the
$ Q\bar{Q} $ pair,$ \begin{aligned}[b] \frac{\pi F_{Q\bar{Q}}}{\sqrt{\lambda}} =& \int_0^{z_0} {\rm d}{z} (\sqrt{\frac{k_2(z)k_1(z)}{k_2(z)-k_2(z_0)}}-\sqrt{k_2(z\rightarrow 0)}) \\ & - \int_{z_0}^\infty \sqrt{k_2(z\rightarrow 0)} {\rm d}{z}. \end{aligned} $
(22) The inter-quark distance of the
$ Q\bar{Q} $ pair is$ \begin{aligned}[b] r =& 2\int_0^{L/2} {\rm d}x = 2\int_0^{z_0} \frac{{\rm d}x}{{\rm d}z} {\rm d}z \\=&2 \int_0^{z_0} \left[\frac{k_2(z)}{k_1(z)} \left(\frac{k_2(z)}{k_2(z_0)}-1\right)\right]^{-1/2} {\rm d}{z}. \end{aligned} $
(23) Following the discussions on the running of the QCD coupling [98–102], Refs. [7, 103] define a running coupling constant from the perturbative short- and long-distance relations for the singlet free energy as
$ \begin{equation} \alpha_{Q\bar{Q}}=\frac{3 r^{2}}{4} \frac{\mathrm{d} F_{Q\bar{Q}}}{\mathrm{d} r}. \end{equation} $
(24)
Running coupling constant at finite chemical potential and magnetic field from holography
- Received Date: 2021-12-29
- Available Online: 2022-07-15
Abstract: According to gauge/gravity duality, we use an Einstein-Maxwell-dilaton (EMD) model to study the running coupling constant at finite chemical potential and magnetic field. First, we calculate the effect of temperature on the running coupling constant and find the results are qualitatively consistent with lattice guage theory. Subsequently, we calculate the effect of chemical potential and magnetic field on running coupling. It is found that the chemical potential and magnetic field both suppress the running coupling constant. However, the effect of the magnetic field is slightly larger than that of chemical potential for a fixed temperature. Compared with the confinement phase, the magnetic field has a large influence on the running coupling in the deconfinement phase.