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\begin{document}$ {\cal{B}}\left(K_1^{-}(1270) \rightarrow K^{-} \pi^{+} \pi^{-}\right)=\frac{1}{3} {\cal{B}}_{K_1 \rightarrow K \rho}+\frac{4}{9} {\cal{B}}_{K_1 \rightarrow K^* \pi}+$\end{document} \begin{document}$ {\cal{B}}_{K_1 \rightarrow K \omega} \times {\cal{B}}_{\omega \rightarrow \pi+\pi^{-}}+{\cal{B}}_{K_1 \rightarrow K f_0}, {\cal{B}}\left(\bar{K}_1^0(1270) \rightarrow\right.$\end{document} \begin{document}$ \left.K^{-} \pi^{+} \pi^0\right)=\frac{2}{3} {\cal{B}}_{K_1 \rightarrow K \rho}+\frac{4}{9} {\cal{B}}_{K_1 \rightarrow K^* \pi}.$\end{document} -
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